BASIC ELECTRONICS - OD1633 - LESSON 1/TASK 2
Given:
R1 = 10 Ohms
IR1 = 5 amps
R2 = 25 Ohms
IR2 = 2 amps
R3 = 50 Ohms
IR3 = 1 amp
P = I2 R
Solution:
PR1 = (IR1)2 x R1
PR1 = (5 amps)2 x 10 Ohms
PR1 = 250 watts
PR2 = (IR2)2 x R2
PR2 = (2 amps)2 x 25 Ohms
PR2 = 100 watts
PR3 = (IR3)2 x R3
PR3 = (1 amp)2 x 50 Ohms
PR3 = 50 watts
PT = PR1 + PR2 + PR3
PT = 250 watts + 100 watts + 50 watts
PT = 400 watts
Since the total current and the source voltage are known, the total power
can also be computed by:
Given:
Es = 50 volts
IT = 8 amps
Solution:
PT = Es x IT
PT = 50 volts x 8 amps
PT = 400 watts
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