MACHINE SHOP CALCULATION - OD1640 - LESSON 2/TASK 3
(10) Side adjacent = side opposite tangent
(11) Hypotenuse = side opposite sine
(12) Hypotenuse = side adjacent cosine
f.
Procedure for using these Rules.
(1) In a right triangle, both the known and unknown sides (opposite,
adjacent, and hypotenuse) of the problem are named.
(2) Choose from among the previous rules; select one that fits the given
numerical values.
(3) Substitute the given values in the rule and solve for the unknown.
EXAMPLE
Find side "a" if sin A = 3/5 and side "c" = 20.5 (figure 14 on the following
page).
Here the sine of angle A is given, and "a" is the side opposite.
According to rule (5) in paragraph 3e on page 53, side opposite = hypotenuse
x sine. Substituting 20.5 for hypotenuse and 3/5 for sine, we get: side
opposite = 20.5 x 3/5 = 12.3.
Find "b" if cos A = .44 and "c" = 3.5 (figure 15 on the following page).
Here the cosine of angle A is given, and "b' is the side adjacent.
According to rule (8) in paragraph 3e on page 53, side adjacent = hypotenuse
x cosine.
Substituting 3.5 for hypotenuse and .44 for cosine, the side
adjacent = 3.5 x .44 = 1.54.
Find "a" if tan A = 11/3 and "b" = 2 5/11 (figure 16 on page 56). Here the
tangent of angle A is given, and "a" is the side opposite.
According to
rule (6) in paragraph 3e on page 53, side opposite = side adjacent x
tangent. Substituting 2 5/11 for side adjacent and 11/3 for tangent, side
opposite = 2 5/11 x 11/3 = 9.
Find "b" if cot A = 4 and "a" = 17 (figure 17 on page 56).
Here the
cotangent of angle A is given, and "b" is the side adjacent. According to
rule (9) in paragraph 3e on page 53, side adjacent = side opposite x
cotangent.
Substituting 17 for side opposite and 4 for cotangent, side
adjacent = 17 x 4 = 68.
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