EXAMPLE

Find the distance across the flats of the largest hexagon which may be cut

from a 15 inch (or 15 cm) diameter bar of round mild steel stock.

SOLUTION

A hexagon is a polygon bounded by six flat sides.

Each flat side is the

opposite side of a 60,, angle. The 15 inch (or 15 cm) diameter of the round

viewed from either end.

In paragraph 9c(2) on page 75, and Table 11 on the previous page, we found

that sine 60,, = .866.

According to Rule (5)(see page 53), the opposite side = hypotenuse x sine.

Therefore:

Distance across flats = diameter of stock x .866

(opposite side)

Distance across = 15 in x .866

15 cm x .866

flats (opposite

side)

or

= 12.99 in

12.99 cm

EXAMPLE

Find the diameter of round bar stock required to cut a hexagon 9 cm across

flats.

SOLUTION