MACHINE SHOP CALCULATION - OD1640 - LESSON 2/TASK 3
EXAMPLE
Find the distance across the flats of the largest hexagon which may be cut
from a 15 inch (or 15 cm) diameter bar of round mild steel stock.
SOLUTION
A hexagon is a polygon bounded by six flat sides.
Each flat side is the
opposite side of a 60,, angle. The 15 inch (or 15 cm) diameter of the round
stock is the hypotenuse of each of six 60,, angles in the round stock when
viewed from either end.
In paragraph 9c(2) on page 75, and Table 11 on the previous page, we found
that sine 60,, = .866.
According to Rule (5)(see page 53), the opposite side = hypotenuse x sine.
Therefore:
Distance across flats = diameter of stock x .866
(opposite side)
Distance across = 15 in x .866
15 cm x .866
flats (opposite
side)
or
= 12.99 in
12.99 cm
EXAMPLE
Find the diameter of round bar stock required to cut a hexagon 9 cm across
flats.
SOLUTION
77
Previous Page
