ELECTRONIC PRINCIPLES - OD1647 - LESSON 1/TASK 1
The alternating voltage is assumed to be an effective value
(since it is not specified to be otherwise). Apply the Ohm's
Law formula.
Eeff
Ieff =
R
120 volts
Ieff = ---------
20 Ohms
Ieff = 6 amperes
The problem, however, asked for the average value of current
(Iavg). To convert the effective value of current to the average
value of current, you must first determine the peak or maximum
value of current, Imax.
Imax = 1.414 x Ieff
Imax = 1.414 x 6 amperes
Imax = 8.484 amperes
You can now find Iavg. Just substitute 8.484 amperes in the Iavg
formula and solve for Iavg.
Iavg = 0.636 x Imax
Iavg = 0.636 x 8.484 amperes
Iavg = 5.4 amperes (rounded off to one decimal place)
Remember, you can use the Ohm's Law formulas to solve for any
purely resistive ac circuit problem. Use the formulas in the
same manner as you would to solve for a dc circuit problem.
6. Conclusion
In the preceding task, we discussed magnetism, analysis of
inductive and capacitive circuits, and the production of
alternating current. In the next task, we will discuss the
basic fundamentals of semiconductors, including PNP and NPN
transistors.
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