voltages.

When two opposing sources are inserted into a circuit, current

flow would be in a direction determined by the larger source.

Examples of series aiding and opposing sources are shown in figure 31 on the

previous page.

A simple solution may be obtained for a multiple-source circuit through the

use of Kirchhoff's voltage law. In applying this method, the same procedure

is used for the multiple-source circuit as was used above for the single-

source circuit. This is demonstrated by the following.

Example: Using Kirchhoff's voltage equation, find the amount of current in

the circuit shown in figure 32.

FIGURE 32.

SOLVING FOR CIRCUIT CURRENT USING KIRCHHOFF'S VOLTAGE

CURRENT.

Solution: As before, a direction of current flow is assumed and polarity

signs are placed on the drawing. The loop equation will be started at point

A.

E2 + ER1 + E1 + E3 + ER2 = 0

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