To solve the problem, a circuit diagram is first drawn and labeled (figure

24, on the following page).

Given:

R1 = 20 Ohms

R2 = 30 Ohms

R3 = 50 Ohms

I = 2 amperes

Solution:

ET = E1 + E2 + E3

FIGURE 24.

SOLVING FOR APPLIED VOLTAGE IN A SERIES CIRCUIT.

E1 = R1 x I1 (I1 = The current through resistor Rl)

E2 = R2 x I2

E3 = R3 x I3

Substituting:

ET = (R1 x I1) + (R2 x I2) + (R3 x I3)

ET = (20 Ohms x 2 amps) + (30 Ohms x 2 amps) + (50 Ohms x 2 amps)