The alternating voltage is assumed to be an effective value

(since it is not specified to be otherwise). Apply the Ohm's

Law formula.

Eeff

Ieff =

R

120 volts

Ieff = ---------

20 Ohms

Ieff = 6 amperes

The problem, however, asked for the average value of current

(Iavg). To convert the effective value of current to the average

value of current, you must first determine the peak or maximum

value of current, Imax.

Imax = 1.414 x Ieff

Imax = 1.414 x 6 amperes

Imax = 8.484 amperes

You can now find Iavg. Just substitute 8.484 amperes in the Iavg

formula and solve for Iavg.

Iavg = 0.636 x Imax

Iavg = 0.636 x 8.484 amperes

Iavg = 5.4 amperes (rounded off to one decimal place)

Remember, you can use the Ohm's Law formulas to solve for any

purely resistive ac circuit problem. Use the formulas in the

same manner as you would to solve for a dc circuit problem.

6. Conclusion

In the preceding task, we discussed magnetism, analysis of

inductive and capacitive circuits, and the production of

alternating current. In the next task, we will discuss the

basic fundamentals of semiconductors, including PNP and NPN

transistors.

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